How to Approach Each Question
Five problems, two CILOs, and a mark sheet that will punish rushed working. The questions span vapour-liquid equilibrium, activity coefficient modelling, bubble point iteration, Gibbs free energy-based equilibrium constants, and equilibrium conversion at operating conditions. Here is exactly how to set up each one — step by step — before you put pen to paper.
This problem sheet covers two distinct competency areas: vapour-liquid equilibrium modelling (CILO 3) and chemical reaction equilibrium (CILO 4). The marks are split unevenly — Problems 4 and 5 together account for 50 marks — so if you lose the thread on the Gibbs energy section, that is half your grade. Read the setup for each problem before you write a single number. Units, sign conventions, and the correct form of each equation matter more here than in most assessments.
What This Guide Covers
Assignment Overview and Mark Distribution
Before anything else, understand what each problem is actually worth and which CILO it assesses. The mark split tells you where to spend your time.
| Problem | Topic | CILO | Marks | Key Equations |
|---|---|---|---|---|
| 1 | VLE — activity coefficients, gE/RT, 1-parameter Margules | CILO 3 | 15 (5+5+5) | Modified Raoult’s law, Margules equation |
| 2 | VLE dataset — activity coefficients + van Laar model fitting | CILO 3 | 20 | Modified Raoult’s law, van Laar equations |
| 3 | Bubble point temperature — methanol/water system | CILO 3 | 15 | Antoine correlation, modified Raoult’s law, iterative method |
| 4 | Equilibrium constant vs T from Gibbs free energy data | CILO 4 | 25 (20+5) | ΔG°rxn = −RT ln Ka |
| 5 | Equilibrium conversion from experimental Ka expression | CILO 4 | 25 (20+5) | Ka expression, stoichiometric table, fugacity/pressure terms |
The assignment explicitly states it must be hand-written. Marks are deducted if it is not. Scan or photograph each page clearly, compile into a single PDF, and upload to Moodle or the instructor’s email. Make sure equations, subscripts, and Greek letters are legible in the scan — blurry photos of pencil working will cost you presentation marks even if the method is correct.
Problem 1 — VLE, Activity Coefficients, gE/RT, and 1-Parameter Margules
You have a single data point: x1 = 0.27, y1 = 0.37, P = 110.1 kPa at 20°C. Saturation pressures are P1sat = 90.2 kPa and P2sat = 120.4 kPa. Three sub-questions, five marks each.
Apply Modified Raoult’s Law to Each Component Separately
Modified Raoult’s law states: yiP = xiγiPisat. Rearrange for γi:
γ1 = (y1 × P) / (x1 × P1sat) and γ2 = (y2 × P) / (x2 × P2sat)Remember: y2 = 1 − y1 = 0.63 and x2 = 1 − x1 = 0.73. Calculate both γ values numerically and show each step. Both should be close to 1 but not exactly 1 — this is a non-ideal system. If you get exactly 1 for either component, check you used the right y and x values.
Use the Excess Gibbs Energy Relationship at This Composition
The molar excess Gibbs energy is related to activity coefficients by:
gE/RT = x1 ln(γ1) + x2 ln(γ2)Plug in x1, x2, and the γ values you calculated in Part A. Take natural logs — not log10. The result is dimensionless. Show the numerical substitution clearly rather than just writing the final number. Five marks here means the marker wants to follow your working.
Identify the Margules Constant A from One of the Activity Coefficients
The one-parameter Margules model assumes symmetric non-ideality. For a binary system:
ln(γ1) = A·x22 and ln(γ2) = A·x12You have only one data point, so calculate A from each equation and note whether they agree. In a strictly symmetric system they should be the same. Use the average if they differ slightly. Clearly state your value of A with units (it is dimensionless) and show how it was derived from your Part A γ values. Do not use a different value of A for each component — the whole point of the one-parameter model is a single constant.
Problem 2 — n-Heptane / Toluene — Van Laar Model Fitting
Twenty marks. You have 9 interior data points (excluding pure component endpoints) and Antoine-type saturation pressure correlations. This is the most calculation-heavy problem in the CILO 3 section. Organise your working in a table.
Convert Temperature Before Using the Antoine Correlations
The correlations are given in Kelvin but the experimental data is at 25°C. T = 25 + 273.15 = 298.15 K. Calculate P1sat and P2sat at this temperature first. Check the valid range stated in the problem: 323–523 K for both. 298.15 K is below this range — that is a given constraint of the problem and the instructor knows this, so use the correlations anyway. Note the extrapolation in your working.
Calculate Activity Coefficients at Each Interior Data Point
For each of the 9 x1 values (0.029 through 0.934), apply modified Raoult’s law to get γ1 and γ2. Use the corresponding y1, y2 = 1−y1, and P values from the table. Build a results table with columns: x1, y1, P, γ1, γ2. This table is your primary output and makes the van Laar fitting much easier to show systematically.
Fit the Van Laar Model Parameters A12 and A21
The van Laar equations are: ln(γ1) = A12 / (1 + A12x1/A21x2)2 and the symmetric form for γ2. To find A12 and A21, linearise the model using the Carlson-Colburn method: plot 1/√(ln γ1) vs x1/x2 and 1/√(ln γ2) vs x2/x1. The slopes and intercepts give A12 and A21 directly. Alternatively, use data at the infinite-dilution limits (x1 → 0 and x1 → 1) to extract the parameters from your calculated γ values at the lowest and highest compositions.
As x1 → 0, ln(γ1∞) = A12. As x2 → 0 (x1 → 1), ln(γ2∞) = A21. Your data at x1 = 0.029 is close to the first limit and x1 = 0.934 is close to the second. Use these points to get initial estimates of A12 and A21, then verify they give a reasonable fit across the full composition range. This is faster than regression and acceptable at this level.
Problem 3 — Bubble Point Temperature for Methanol / Water at 101.3 kPa
Fifteen marks. Bubble point calculation at fixed pressure. You are given both the Antoine correlations and the activity coefficient expressions — so the γi are not constant here, they depend on composition and temperature. This makes the iteration slightly more involved than a simple Raoult’s law bubble point.
The Bubble Point Condition Is: Σ(xi γi Pisat/P) = 1
The feed is 20 mol% methanol (x1 = 0.2) and 80 mol% water (x2 = 0.8) at P = 101.3 kPa. You need to find T such that this sum equals exactly 1.0. The γ values are given as functions of x1 and x2 only — composition is fixed — so the only variable you iterate on is T through the Antoine equations.
Iteration procedure:1. Guess an initial T. A reasonable start: the boiling point of water at 101.3 kPa is ~373 K. Methanol boils lower (~338 K). For a water-rich mixture try 360–365 K as a first guess.
2. Evaluate P1sat(T) and P2sat(T) using the Antoine correlations. Note these use T in Kelvin directly in the denominator expressions as written.
3. Evaluate γ1 and γ2 using the given expressions at x1 = 0.2, x2 = 0.8.
4. Compute Σ = x1γ1P1sat/P + x2γ2P2sat/P.
5. If Σ > 1, T is too high (saturation pressures are too large). If Σ < 1, T is too low. Adjust and repeat. 5–8 iterations typically converge to ±0.1 K.
The correlations given are written as ln(Psat) = A − B/(C + T). The constants A, B, C are specific to each component and differ from the standard Antoinecorrection for log10. Do not mix up the two forms. Also check whether the denominator term contains +T or −T (the forms in the problem have −T inside the denominator bracket). Substitute values mechanically and double-check your Psat results against any known boiling point reference before proceeding with the iteration.
Once you have converged on T, calculate the vapour compositions: yi = xiγiPisat/P. Confirm they sum to 1.0 as a check. Report both T (in K and °C) and the y values.
Problem 4 — Equilibrium Constant vs Temperature from Gibbs Free Energy Data
Twenty-five marks, split 20+5. The reaction is methylcyclohexane ⇌ toluene + 3H2. You have tabulated Gibbs free energies of formation for the reactant and products at nine temperatures from 298 K to 1000 K.
Calculate ΔG°rxn at Each Temperature
Apply ΔG°rxn = Σ νi ΔG°f,i. Stoichiometry: νA = −1 (reactant), νB = +1 (toluene), νH₂ = +3. You are only given data for A and B — note that ΔG°f for H2 is zero by convention (it is an element in its standard state). So ΔG°rxn(T) = ΔG°f,B(T) − ΔG°f,A(T). Calculate this at all nine temperatures and set up a table.
Convert ΔG°rxn to Ka at Each Temperature
The relationship is ΔG°rxn = −RT ln(Ka), so Ka = exp(−ΔG°rxn/RT). Use R = 8.314 J/(mol·K). Critical: make sure ΔG°rxn is in J/mol when multiplied with R in J/(mol·K) — or convert both to kJ consistently. A single unit inconsistency here will give Ka values that are off by factors of thousands.
Develop the Ka vs T Expression
Plot ln(Ka) vs 1/T (K−1). For many reactions this is approximately linear — the slope gives −ΔH°/R and the intercept gives ΔS°/R via the van’t Hoff equation. Fit a straight line through your nine data points (linear regression by hand: use the slope formula Σ(xy − x̄ȳ)/Σ(x² − x̄²) where x = 1/T and y = ln Ka). Write the final expression as ln(Ka) = a/T + b, then exponentiate to give Ka as a function of T.
Evaluate Ka at 650 K Using Your Expression
The 5-mark sub-question simply asks you to substitute T = 650 K into the expression you derived. Show the substitution clearly. Also calculate Ka(650 K) directly from the ΔG° approach to cross-check — they should be close but not identical since your expression is a linear regression fit. If the two values differ significantly, your regression has an error.
A negative ΔG°rxn means spontaneous reaction under standard conditions → Ka > 1. A positive ΔG°rxn means non-spontaneous → Ka < 1. The dehydrogenation of methylcyclohexane is endothermic and becomes more favourable at higher temperatures — so Ka should increase with T. If your Ka values decrease as T increases, you have a sign error somewhere in ΔG°rxn. The property data from NIST Webbook (webbook.nist.gov) can be used to sanity-check your ΔG°f values at 298 K against published standards.
Problem 5 — Equilibrium Conversion and Composition at 5 bar, 360°C
Twenty-five marks (20+5). The experimental Ka expression is given as Ka = 3600 exp[−217650/R × (1/T − 1/650)], with R in kJ/(kmol·K). Pure methylcyclohexane feed.
Substitute T = 360°C = 633.15 K, P = 5 bar Into the Given Expression
Convert temperature to Kelvin first: T = 360 + 273.15 = 633.15 K. Then calculate Ka:
Ka = 3600 × exp[−217650/R × (1/633.15 − 1/650)]Use R = 8314 kJ/(kmol·K) as stated. The exponent will be negative and small in magnitude. Work through it carefully — the difference (1/633.15 − 1/650) is a small negative number, so the overall exponent is positive, meaning Ka > 3600. If your Ka comes out less than 3600, recheck the sign of (1/T − 1/650) at T < 650 K.
Define Equilibrium Conversion ξ and Write Mole Fractions
Basis: 1 mole of pure methylcyclohexane (A). Let ξ = equilibrium conversion (fraction of A that reacts). The reaction is A ⇌ B + 3H2.
Moles at equilibrium:A: 1 − ξ B: ξ H2: 3ξ Total: 1 + 3ξ
Mole fractions:
yA = (1 − ξ)/(1 + 3ξ) yB = ξ/(1 + 3ξ) yH₂ = 3ξ/(1 + 3ξ)
Account for the Pressure Dependence — This Reaction Produces More Moles
For an ideal gas mixture, Ka = Ky × (P/P°)Δν where Δν = 1 + 3 − 1 = 3 (net moles of gas produced). Take P° = 1 bar as the standard state pressure.
Ky = yB × yH₂3 / yA = [ξ/(1+3ξ)] × [3ξ/(1+3ξ)]3 / [(1−ξ)/(1+3ξ)]Ka = Ky × (P/P°)3 = Ky × 53 = Ky × 125
Rearrange to: Ky = Ka/125. Substitute the mole fraction expressions in terms of ξ and solve for ξ. This is a nonlinear equation — solve numerically by trial and error or by rearranging and iterating. A reasonable first guess is ξ = 0.7–0.9 for a high-temperature dehydrogenation.
Once you have ξ, calculate the equilibrium mole fractions yA, yB, and yH₂ directly from the expressions in your stoichiometric table. Report them as percentages or fractions — both are acceptable but be consistent. Check they sum to 1.00. If they do not, recalculate. Five clean marks for correct substitution of ξ into three expressions.
Where Students Lose Marks
Using log10 Instead of ln in the Gibbs/Ka Calculation
ΔG° = −RT ln(Ka) uses natural logarithm. The Antoine correlations in this problem also use ln (not log10). Mixing the two kills your Ka values and the downstream conversion calculation.
Write “ln” Explicitly at Every Step
In hand-written work, write ln(…) in full every time it appears. Do not abbreviate to log without specifying the base. Markers deduct marks for ambiguous notation.
Forgetting the (P/P°)Δν Term in Problem 5
Students frequently write Ka = Ky without the pressure correction. For a reaction where Δν ≠ 0, this is wrong and gives the incorrect ξ. At 5 bar and Δν = 3, the correction factor is 125 — not negligible.
State Your Standard Pressure and Δν Explicitly
Write out Δν = products − reactants = (1+3) − 1 = 3, state P° = 1 bar, and show Ka = Ky(P/P°)3 before substituting numbers. This earns method marks even if arithmetic slips.
Skipping Unit Conversion in the Antoine Equation
The correlations for n-heptane/toluene specify a Kelvin range. Temperature must be in Kelvin before substitution. Substituting 25 (Celsius) instead of 298.15 K produces dramatically wrong saturation pressures.
Write the Temperature Conversion As Part of Your Working
Show “T = 25 + 273.15 = 298.15 K” explicitly at the start of Problems 2 and 3 before any calculation. This is one line and secures the unit conversion step for the marker.
Inconsistent R Values Across Problems 4 and 5
Problem 4 uses R = 8.314 J/(mol·K). Problem 5 states R in kJ/(kmol·K). The numerical value is 8314 kJ/(kmol·K). If you use 8.314 in Problem 5’s Ka expression the exponent is wrong by a factor of 1000.
Re-read the Units Stated in Each Problem Before Substituting R
Problem 5 explicitly states “R is in kJ/(kmol·K).” That means R = 8314 in that expression. Note this at the top of your Problem 5 solution so the marker can see you used the correct value.
Hand-Written Submission Requirements
This is not optional formatting guidance — it affects your grade directly.
Pre-Submission Checklist
Recommended Reference
Smith, J.M., Van Ness, H.C., and Abbott, M.M. — Introduction to Chemical Engineering Thermodynamics (8th ed., McGraw-Hill). Chapters 10–14 cover VLE, activity coefficients, and reaction equilibrium in the detail this problem sheet requires. The worked examples in these chapters use exactly the equation forms given in your problems.
Free External Resource
NIST WebBook (webbook.nist.gov) provides tabulated thermochemical data including Gibbs free energies of formation for methylcyclohexane and toluene. Use it to cross-check the ΔG°f values given in Problem 4 at 298 K before you run all nine calculations — catching a data transcription error early saves a lot of rework.
Frequently Asked Questions
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Before You Write a Single Number
Read through all five problems first. Identify which equations you will use and confirm the units demanded by each. Problems 1–3 are self-contained — you will not need output from one to solve another. Problems 4 and 5 are connected: the dehydrogenation reaction and its equilibrium properties run through both. But Problem 5 gives you its own Ka expression, so you do not need Problem 4’s result to solve it.
The most common point of failure in this type of assessment is not getting the concept wrong — it is getting the setup wrong and then executing perfectly on incorrect foundations. State your assumptions. Write your given data. Show your unit conversions. Those three habits protect your method marks even when a calculation goes sideways.
The assignment is hand-written and scanned. Budget time for that. A clear, well-organised submission is faster to mark and faster to give the benefit of the doubt to when a step is ambiguous.
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